`y = sqrtx + 1/sqrtx`

y = x+sqrtx+1/sqrtx

Find dy/dx for the following functions: y= x+ sqrtx + (1/sqrtx)

Evaluate : int ( sqrtx + 1/sqrtx ) dx

If x = 2 + sqrt3 then the value of sqrtx + 1/sqrtx is

y = sqrt(2 -sqrtx)

y = sqrt(1+sqrtx)

If sqrtx- 1/sqrtx= sqrt 5 , then x^2+1/x^2 is equal to: यदि sqrtx- 1/sqrtx= sqrt 5 है, तो x^2+1/x^2 का मान क्या होगा ?

If x = 3 + 2 sqrt2 , find the value sqrtx - (1)/(sqrtx)