If `X=8.00+-0.04` cm and `Y=4.00+-0.04` cm, then `(X)/(Y)` should be expressed as
(1) `2.00+-0.01`
(2) `2.00+-0.02`
(3) `2.00+-0.03`
(4) `2.00+-0.04`

Solve : 0.04x+0.02y= 5 and 0.5( x-2) -0.4 y = 29

{:(0.04x + 0.02y = 5),(0.5(x - 2) - 0.4y = 29):}

If A=[(0,2),(0,0)] then A^(3) is equal to

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Determine which of the following can be probability distributions of a random variable X: (i) X: 0 1 2 (ii) X: 0 1 2 P(X): 0.4 0.4 0.2 P(X): 0.6 0.1 0.2 (iii) X: 0 1 2 3 4 P(X): 0.1 0.5 0.2 -0.1 0.3

The points (-a,-b) , (0,0) . (a,b) and (a^(2),a^(3)) are

Where are the point: (0,0,-4)