Let `y=y(x)` is the solution of the different equation `dy+ e^(x)tan^(2)xdx=ydx` in `x in(0,(pi)/(2))`. If `lim_(x->0^+) y(x) =0`, then area bounded by `y=y(x)` and `f(x)=e^x(x^2-tanx)` is (use `e=2.71`)