Home
Class 14
MATHS
The number of factors 48 is...

The number of factors 48 is

A

10

B

9

C

11

D

12

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of factors of 48, we can follow these steps: ### Step 1: Prime Factorization First, we need to find the prime factorization of 48. - 48 can be divided by 2 (the smallest prime number): \[ 48 \div 2 = 24 \] - 24 can also be divided by 2: \[ 24 \div 2 = 12 \] - 12 can also be divided by 2: \[ 12 \div 2 = 6 \] - 6 can also be divided by 2: \[ 6 \div 2 = 3 \] - 3 is a prime number and cannot be divided further. So, the prime factorization of 48 is: \[ 48 = 2^4 \times 3^1 \] ### Step 2: Use the Formula for Finding the Number of Factors The formula to find the number of factors from the prime factorization \( p_1^{e_1} \times p_2^{e_2} \times \ldots \times p_n^{e_n} \) is: \[ (e_1 + 1)(e_2 + 1) \ldots (e_n + 1) \] where \( e_1, e_2, \ldots, e_n \) are the exponents in the prime factorization. For 48, we have: - \( e_1 = 4 \) (from \( 2^4 \)) - \( e_2 = 1 \) (from \( 3^1 \)) Using the formula: \[ (4 + 1)(1 + 1) = 5 \times 2 = 10 \] ### Conclusion Thus, the total number of factors of 48 is **10**. ---
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LCM AND HCF

    BHARDWAJ ACADEMY|Exercise CHAPTER EXERCISE |35 Videos
  • GEOMETRY

    BHARDWAJ ACADEMY|Exercise Chapter Exercise (Pervious Years Questions)|25 Videos
  • MENSURATION

    BHARDWAJ ACADEMY|Exercise CHAPTER EXERCISE (Previous Years. Questions)|33 Videos