Home
Class 14
MATHS
The sides of a triangle are 6.5 cm, 10 c...

The sides of a triangle are 6.5 cm, 10 cm and x cm, where x is a positive number. What is the smallest possible value of x among the following.

A

3.5

B

4

C

4.5

D

2.8

Text Solution

AI Generated Solution

The correct Answer is:
To find the smallest possible value of \( x \) for the triangle with sides 6.5 cm, 10 cm, and \( x \) cm, we will use the triangle inequality theorem. According to this theorem, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. We will apply this theorem to our triangle. ### Step 1: Apply the Triangle Inequality Theorem We have three sides: 6.5 cm, 10 cm, and \( x \) cm. We need to set up inequalities based on the triangle inequality theorem. 1. \( 6.5 + 10 > x \) 2. \( 6.5 + x > 10 \) 3. \( 10 + x > 6.5 \) ### Step 2: Solve the Inequalities **Inequality 1:** \[ 6.5 + 10 > x \] \[ 16.5 > x \] This means: \[ x < 16.5 \] **Inequality 2:** \[ 6.5 + x > 10 \] \[ x > 10 - 6.5 \] \[ x > 3.5 \] **Inequality 3:** \[ 10 + x > 6.5 \] \[ x > 6.5 - 10 \] \[ x > -3.5 \] Since \( x \) is a positive number, this inequality does not provide a new constraint. ### Step 3: Combine the Results From the inequalities we derived: - From Inequality 1, we have \( x < 16.5 \). - From Inequality 2, we have \( x > 3.5 \). Thus, we can conclude: \[ 3.5 < x < 16.5 \] ### Step 4: Determine the Smallest Possible Value of \( x \) The smallest possible value of \( x \) that satisfies the inequality \( x > 3.5 \) is just above 3.5. However, since we are looking for a specific value among given options, we would choose the smallest option that is greater than 3.5. ### Conclusion The smallest possible value of \( x \) is any value greater than 3.5. If options are provided, select the smallest one that is greater than 3.5. ---
Promotional Banner

Topper's Solved these Questions

  • MENSURATION

    BHARDWAJ ACADEMY|Exercise CHAPTER EXERCISE |47 Videos
  • LCM AND HCF

    BHARDWAJ ACADEMY|Exercise CHAPTER EXERCISE |35 Videos
  • NUMBER SYSTEM

    BHARDWAJ ACADEMY|Exercise CHAPTER EXERCISE |100 Videos
BHARDWAJ ACADEMY-MENSURATION -CHAPTER EXERCISE (Previous Years. Questions)
  1. The scale of a map is given as 1:10000. On the map, a forest occupies ...

    Text Solution

    |

  2. 42 cubes each of side 1 cm area glured together to form a solid cubo...

    Text Solution

    |

  3. The area of a trapezium-shaped field is 720m^(2), the distance between...

    Text Solution

    |

  4. The base of an isosceles DeltaABC is 48 cm and its area is 168cm^(2). ...

    Text Solution

    |

  5. The area of a square is (16)/(pi) of the area of a circle. The ratio o...

    Text Solution

    |

  6. Four times the area of the curved surface of a cylinder is equal to 6 ...

    Text Solution

    |

  7. If a, b and c are respectively the number of faces, edges and vertices...

    Text Solution

    |

  8. The base radii of two cylinders are in the ratio 2 : 3 and their heigh...

    Text Solution

    |

  9. The perimeter of a trapezium is 104 cm, the lengths of its non-paralle...

    Text Solution

    |

  10. If each edge of a solid cube is increased by 150%, the percentage incr...

    Text Solution

    |

  11. The internal base of a rectangular box is 15 cm long and 12 (1)/(2) c...

    Text Solution

    |

  12. The perimeter of a trapezium is 58 cm and sum of its non-parallel side...

    Text Solution

    |

  13. The sides of a triangle are 6.5 cm, 10 cm and x cm, where x is a posit...

    Text Solution

    |

  14. ABCD is a quadrilateral in which BD = 40 cm. The lengths of the perpen...

    Text Solution

    |

  15. Two sheets of paper with measure22 cm by 28 cm are taken . Each sheet...

    Text Solution

    |

  16. A wire of 5024 m length is in the form of a square. It is cut and m...

    Text Solution

    |

  17. Two sides of a right triangle measure 15 cm and 17 cm . Which of the f...

    Text Solution

    |

  18. A tank is in the form of a cuboid. It holds a maximum of 540m^(3) wate...

    Text Solution

    |

  19. The ratio of the areas of two equilateral triangles is 16:9. If the pe...

    Text Solution

    |

  20. The area of a triangle is equal to the area of a circle whose perimete...

    Text Solution

    |