If MASTER is coded as 411259 then POWDER will be coded as .

Options

A. `overline(7)overline(6)overset(.)(5)43 overline(9)`
B. `overline(7)6overset(.)(5)43 overline(9)`
C. `overline(7)overline(6)overset(.)(5)45 overline(9)`
D. `overline(7)overset(.)(6)overline(5)5overline(4) overline(9)`

Answer

C

Explanation

The pattern is as follows : Sum of the digits of the original position of the alphabets = `overline("Number")` and ten.s place digit of the original position of alphabets = numbers .
i.e., M = 13 = 1 + 3 `overline(4)`.
A = 1, S = 19 = Ten.s place digit .
= 1, T = 20 = Ten.s place digit = 2 ,
E = 5 , R = 18 = 1 + 8 = `overline(9)`
So , MASTER is coded as `overline(4)1overset(.)(1)overset(.)(2)5 overline(9)`
Therefore , POWER is coded as `overline(7) overline(6)overset(.)(5)45.overline(9)`