`7/13+(-9)/13=(__+(-9))/13=-/13`

13/5-5/13 =

5/13-5/13 =

Show that the three lines with direction cosines (12)/(13),(-3)/(13),(-4)/(13),4/(13),(12)/(13),3/(13);3/(13),(-4)/(13),(12)/(13) are mutually perpendicular.

Show that the three lines with direction cosines (12)/(13),(-3)/(13),(-4)/(13);4/(13);(12)/(13),3/(13);3/(13),(-4)/(13),(12)/(13) are mutually perpendicular.

4/13+9/13+2/13=-/13

For two events A and B, P(A)=7/13, P(B)=9/13 and P(AnnB)=4/13 . Find the value of P(A//B) .

Evaluate: (-4)/(13)-((-9))/(25)-(3)/(10)

Choose the correct option (-5)/(13)+?=-1 (a) 8/(13) (b) (-8)/(13) (c)(-18)/(13) (d) (18)/(13)

Fill in the blanks: (-4)/(13)-(-3)/(26)= (ii) (-9)/(14)+=-1

Find: ((-8))/(13)+((-4))/(13)