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tan4x = (4tanx (1-tan^2x))/(1-6tan^2x+ta...

`tan4x = (4tanx (1-tan^2x))/(1-6tan^2x+tan^4x)`

Answer

Step by step text solution for tan4x = (4tanx (1-tan^2x))/(1-6tan^2x+tan^4x) by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.

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Knowledge Check

  • The general solution of (tan 5x-tan 4x)/(1+ tan 5 x tan 4x)=1 is

    A
    `n pi+pi/4, AA n in Z`
    B
    `n pi pm pi/4, AA n in Z`
    C
    `phi`
    D
    `n pi=pi/6, AA n in Z`

  • lim_(xrarrtan^(-1)3)((tan^2x-2tanx-3)/(tan^2x-4tanx+3)) equals

    A
    1
    B
    2
    C
    0
    D
    3

  • " tan " ((pi)/(4) -x) =(1 - tan x)/( 1+ tan x)

    A
    `tan (x -(pi)/(4))`
    B
    `tan (x + (pi)/(4))`
    C
    `tan ((pi)/(4) -x)`
    D
    `tan((pi)/(4)) - tan(x)`

    • Similar Questions

    Explore conceptually related problems

    The general solution of (tan5x-tan4x)/(1+tan5x tan4x)=1 is

    Solve (tan 3x - tan 2x)/(1+tan 3x tan 2x)=1 .

    (tan(pi/4+x))/(tan(pi/4-x)) = ((1+tanx)/(1-tanx))^(2)

    Evaluate lim_(x to 0) (tan x + 4 tan 2x - 3tan 3x)/(x^(2) tan x)

    " tan " ((pi)/(4) +x) =(1 + tan x)/(1-tan x)

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