`y = x+sqrtx+1/sqrtx `

y = sqrtx + 1/sqrtx

If sqrtx- 1/sqrtx= sqrt 5 , then x^2+1/x^2 is equal to: यदि sqrtx- 1/sqrtx= sqrt 5 है, तो x^2+1/x^2 का मान क्या होगा ?

If x = 2 + sqrt3 then the value of sqrtx + 1/sqrtx is

If x=3+2 sqrt2 , then the value of sqrtx-1/sqrtx is : यदि x=3+2 sqrt2 , तब sqrtx-1/sqrtx का मान :

Evaluate : int ( sqrtx + 1/sqrtx ) dx

If (3(x^2 +1)-7x)/3x =6, x ≠ 0 , then the value of sqrtx + 1/(sqrtx) is: यदि (3(x^2 +1)-7x)/3x =6, x ≠ 0 , है, तो sqrtx + 1/(sqrtx) का मान क्या होगा?

y = sqrt(1+sqrtx)

If y=sqrtx+1/sqrtx then prove that 2x (dy)/(dx)+y=2sqrtx

if y=sqrtx tan^-1sqrtx , then find dy/dx