Distance of a plane 2x+y+2z+5=0 from a point (2,1,0) is

Find the distance of the line 4x+7y+5=0 from the point (1,""""2) along the line 2x-y=0 .

If the sum of the squares of the distances of the point (x, y, z) from the points (a, 0, 0) and (-a, 0, 0) is 2c^(2) , then which are of the following is correct?

A plane passes through (1,-2,1) and is perpendicualr to two planes 2x-2y+z=0" and "x-y+2z=4, then the distance of the plane from the point (1,2,2) is

Find the distance of the plane 2x-y-2z-9=0 from the origin.

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0 . Then find the distance of plane thus obtained from the point A(1,3,6) .

find that the distance of the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/12 and the plane (x-y+z=5) from the point (-1,-5,-10) is

Find the distance of the plane 2x + 5y + sqrt7z + 12= 0 from the origin.

The disatance of the point (1, 0, 2) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=16 , is

A plane P = 0 passing through the point (1, 1, 1) is perpendicular to the planes 2x-y+2z=5 and 3x+6y-2z=7 . If the distance of the point (1, 2, 3) from the plane P = 0 is k units, then the value of 34k^(2) is equal to

The distance of the point (-1, -5, -10) from the point of intersection of the line (x-2)/(2)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=5 is