`(dy/dx)+(2/x)y=sinx`, `x gt 0`

(dy)/(dx ) + 2y =sinx

Solve the differential equation x (dy )/(dx) - y = 2 x^(3), x gt 0

(dy)/(dx) + 2y = e ^(-2x) sinx , given that y=0 when x = 0

(dy)/(dx) =-(y+sinx)/(x) satisfying condition y(0)=1

Solve: (d^2y)/dx^2=x+sinx , given that y=0 and (dy)/(dx)=-1 when x=0

The solution of the differential equation x sin d (dy)/(dx) + ( x cos x + sin x ) y = sinx . When y (0)=0 is

Integrating factor of (dy ) /( dx) +(y)/( x) = x^7 - 8 , ( x gt 0 ) is :

If y = y (x) is the solution curve of the differential equation x^2dy + (y - 1/x) dx = 0, x gt 0 , and y(1) = 1, " then " y (1/2) is equal to

If y = y (x) is the solution curve of the differential equation x^2dy + (y - 1/x) dx = 0, x gt 0 , and y(1) = 1, " then " y (1/2) is equal to

dy/dx+2ytanx=sinx at y=0, when x=pi/3