`sqrt(x+5)+sqrt(20-x)=7`

Solve : log_7log_5 (sqrt(x+5)+sqrt(x))=0

Find the range of f(x) = sqrt(x-1)+sqrt(5-x)

Find the range of f(x)=sqrt(x-1)+sqrt(5-x)

Using properties of proportion, solve for x : (i) (sqrt(x + 5) + sqrt(x - 16))/ (sqrt(x + 5) - sqrt(x - 16)) = (7)/(3) (ii) (sqrt(x + 1) + sqrt(x - 1))/ (sqrt(x + 1) - sqrt(x - 1)) = (4x -1)/(2) . (iii) (3x + sqrt(9x^(2) -5))/(3x - sqrt(9x^(2) -5)) = 5 .

sqrt(-5x^(8))- sqrt(-20x^(8)) + sqrt(-45x^(8)) , where x is a positive real number

The solution of the equation (log)_7(log)_5(sqrt(x+5)+sqrt(x)=0 is...

int_(1)^(7)(log sqrt(x))/(log sqrt(8-x)+log sqrt(x))dx=

Solve sqrt((x-5))-sqrt(9-x)>1,x in Zdot

Solve sqrt(x+5)+sqrt(x+21)=sqrt(6x+40.)