`x=a tantheta`, `y=b sectheta`, `y^2/b^2-x^2/a^2`

If x=a sec theta , y=b tantheta , then x^2/a^2-y^2/b^2 is (A) -1 (B) 0 (C) 1 (D) 2

tantheta-tantheta/2=sectheta/2

(tantheta-sectheta)^2

find tantheta if sectheta+tantheta=x

If x=sectheta-tantheta, y=sectheta+tantheta , then the relation between x and y is:

Solve: tantheta+sectheta=2costheta

If x=sectheta-tantheta , and y=cosectheta+cottheta , then

If a=sectheta-tantheta and b= sectheta+tantheta , then

If x ="cosec"theta - sin theta and y=sectheta - costheta , then the value of x^(2)y^(2)(x^(2) + y^(2) + 3) is:

If 6x=sectheta and (6)/(x)=tantheta , find the value of 9(x^(2)-(1)/(x^(2))) .