If `4tan beta=3,` then `(4sin beta-3cos beta)/(4sin beta+3cos beta)=`

If 4 tan beta = 3 , then (4 sin beta - 3 cos beta)/( 4 sin beta + 3 cos beta)=

If tan (alpha-beta)=(sin 2beta)/(3-cos 2beta) , then

If 2tan alpha=3tan beta, then tan (alpha-beta)=(sin2 beta)/(5-cos2 beta)(b)(cos2 beta)/(5-cos2 beta)(c)(sin2 beta)/(5+cos2 beta)(d) none of these

If 3tan alpha=4tan beta ,then prove that tan(alpha-beta)=(sin beta*cos beta)/(3+sin^(2)beta)=(tan beta)/(4tan^(2)beta+3)

Find the value of, cos alpha cos beta, cos alpha sin beta, -no alpha-sin beta, cos beta, 0 sin alpha cos beta, sin alpha sin beta, cos alpha] |

det[[cos alpha cos beta,cos alpha sin beta,-sin alpha-sin beta,cos beta,0sin alpha cos beta,sin alpha sin beta,cos alpha]]

If Delta=|(sin alpha, cos alpha, sin alpha+cos beta),(sin beta, cos alpha, sin beta+cos beta),(sin gamma, cos alpha, sin gamma+cos beta)| then Delta equals

If sin beta=(12)/(13) then the value of (13sin beta+5sec beta)/(5tan beta+6cos ec beta) is

Evaluate: quad =|cos alpha cos beta cos alpha sin beta-sin alpha-sin beta cos beta0sin alpha cos beta sin alpha sin beta cos alpha|

Evaluate ,,,|cos alpha cos beta,cos alpha sin beta,-sin alpha-sin beta,cos beta,0sin alpha,cos beta,sin alpha sin beta,cos alpha]|