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A man deposited Rs.9000 in a bank at 6% ...

A man deposited Rs.9000 in a bank at 6% per annum for 4yr. For how many years, must another man deposit an amount of Rs.5400 at 5% per annum in another bank so that both of them get the same interest?

A

6yr

B

4yr

C

3yr

D

None of the above

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The correct Answer is:
To solve the problem step by step, we will use the formula for Simple Interest (SI): **Formula for Simple Interest:** \[ \text{SI} = \frac{P \times R \times T}{100} \] Where: - \( P \) = Principal amount - \( R \) = Rate of interest (per annum) - \( T \) = Time (in years) ### Step 1: Calculate the Simple Interest for the first man The first man deposited Rs. 9000 at an interest rate of 6% per annum for 4 years. Using the formula: \[ \text{SI}_1 = \frac{9000 \times 6 \times 4}{100} \] Calculating: \[ \text{SI}_1 = \frac{9000 \times 6 \times 4}{100} = \frac{216000}{100} = 2160 \] ### Step 2: Set up the equation for the second man Let \( T \) be the time (in years) for which the second man deposits Rs. 5400 at 5% per annum. We want to find \( T \) such that the interest earned by both men is the same. Using the formula for the second man: \[ \text{SI}_2 = \frac{5400 \times 5 \times T}{100} \] ### Step 3: Set the interests equal Since both interests are equal: \[ 2160 = \frac{5400 \times 5 \times T}{100} \] ### Step 4: Simplify the equation Multiply both sides by 100 to eliminate the fraction: \[ 216000 = 5400 \times 5 \times T \] Calculating \( 5400 \times 5 \): \[ 5400 \times 5 = 27000 \] Now the equation is: \[ 216000 = 27000 \times T \] ### Step 5: Solve for \( T \) To find \( T \), divide both sides by 27000: \[ T = \frac{216000}{27000} \] Calculating: \[ T = 8 \] ### Conclusion The second man must deposit the amount for **8 years** to earn the same interest as the first man.
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