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A bag has 5 red marbles, 4 green marbles...

A bag has 5 red marbles, 4 green marbles and 3 blue marbles. All marbles are indentical in all respects other than colour. A marble is taken out from the bag without looking into it. What is the probability that it is a non-green marbles?

A

`(1)/(3)`

B

`(2)/(3)`

C

`(7)/(12)`

D

`(5)/(12)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability of drawing a non-green marble from a bag containing red, green, and blue marbles, we can follow these steps: ### Step 1: Identify the total number of marbles in the bag. - The bag contains: - Red marbles: 5 - Green marbles: 4 - Blue marbles: 3 **Total marbles = Red + Green + Blue = 5 + 4 + 3 = 12** ### Step 2: Determine the number of non-green marbles. - Non-green marbles are either red or blue. - The number of non-green marbles is: - Red marbles: 5 - Blue marbles: 3 **Total non-green marbles = Red + Blue = 5 + 3 = 8** ### Step 3: Calculate the probability of drawing a non-green marble. - Probability is calculated as the number of favorable outcomes divided by the total number of outcomes. **Probability of non-green marble = (Number of non-green marbles) / (Total number of marbles)** **Probability = 8 / 12** ### Step 4: Simplify the probability. - Simplifying \( \frac{8}{12} \): - Both the numerator and denominator can be divided by 4. **Probability = \( \frac{8 \div 4}{12 \div 4} = \frac{2}{3} \)** ### Conclusion: The probability that a marble drawn from the bag is a non-green marble is \( \frac{2}{3} \). ---
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