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The interest on sum of money at the end ...

The interest on sum of money at the end of ` 2(1/2) `years is `4/5` of the sum. The rate percent per year is

A

`10%`

B

`20%`

C

`16%`

D

`32%`

Text Solution

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The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Understand the problem We need to find the rate percent per year given that the interest at the end of 2.5 years is \( \frac{4}{5} \) of the principal amount. ### Step 2: Define the variables Let the principal amount be \( P \). The time given is \( 2 \frac{1}{2} \) years, which can be converted into an improper fraction: \[ 2 \frac{1}{2} = \frac{5}{2} \text{ years} \] ### Step 3: Write the formula for Simple Interest The formula for Simple Interest (SI) is: \[ SI = \frac{P \times R \times T}{100} \] Where: - \( SI \) is the Simple Interest - \( P \) is the principal amount - \( R \) is the rate of interest per annum - \( T \) is the time in years ### Step 4: Set up the equation According to the problem, the Simple Interest is \( \frac{4}{5} \) of the principal: \[ SI = \frac{4}{5} P \] Substituting this into the Simple Interest formula gives: \[ \frac{4}{5} P = \frac{P \times R \times \frac{5}{2}}{100} \] ### Step 5: Simplify the equation We can cancel \( P \) from both sides (assuming \( P \neq 0 \)): \[ \frac{4}{5} = \frac{R \times \frac{5}{2}}{100} \] ### Step 6: Cross-multiply to solve for \( R \) Cross-multiplying gives: \[ 4 \times 100 = R \times \frac{5}{2} \times 5 \] \[ 400 = R \times \frac{25}{2} \] ### Step 7: Solve for \( R \) To isolate \( R \), multiply both sides by \( \frac{2}{25} \): \[ R = \frac{400 \times 2}{25} \] \[ R = \frac{800}{25} \] \[ R = 32 \] ### Step 8: Conclusion Thus, the rate percent per year is: \[ \text{Rate} = 32\% \text{ per annum} \]
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