`(-1)/3+[4/9+(-8)/13]=[(-1)/3+4/9]+(-8)/13`

(-5)/8+(-9)/13=(-9)/13+(-5)/8

Re-arrange suitably and find the sum in each of the following: (3)/(5)+(7)/(3)+(9)/(5)+(-13)/(15)+(-7)/(3) (ii) (4)/(13)+(-5)/(8)+(-8)/(13)+(9)/(13)

(9)/(13)+(-8)/(13)+(4)/(3)+(-5)/(8)

Divide :(3)/(5)by(4)/(25) (ii) (-8)/(9)by(4)/(3)(-16)/(21)by(-4)/(3) (iv) (8)/(13)by(3)/(-26)

(-8)/(-13)+(9)/(26)+(30)/(-39)+1=

(16(2)/(5)-12(1)/(15))-:3(4)/(81)=?( a) 1(9)/(19) (b) 1(9)/(13)(c)2(8)/(13) (d) 3(2)/(19) (e) None of these

Simplify: 1/(1+(2/3)/(1+2/3+(8/9)/(1-2/3))) . (11)/(13) (b) (13)/(15) (c) (13)/(11) (d) (15)/(13)