In the reaction `H_2O_2+Na_2CO_3rarrNa_2O_2+CO_2+H_2O` the substance undergoing oxidation is

Options

A. `H_2O_2`
B. `Na_2CO_3`
C. `Na_2O_2`
D. None of these

Answer

To determine which substance is undergoing oxidation in the reaction \( H_2O_2 + Na_2CO_3 \rightarrow Na_2O_2 + CO_2 + H_2O \), we need to analyze the oxidation states of the elements involved in the reaction.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- Reactants: \( H_2O_2 \) (hydrogen peroxide) and \( Na_2CO_3 \) (sodium carbonate).
- Products: \( Na_2O_2 \) (sodium peroxide), \( CO_2 \) (carbon dioxide), and \( H_2O \) (water).

2. **Assign Oxidation States**:
- For \( H_2O_2 \):
- Hydrogen (H) is +1.
- Oxygen (O) is -1.
- Therefore, the oxidation state of oxygen in \( H_2O_2 \) is -1.
- For \( Na_2CO_3 \):
- Sodium (Na) is +1.
- Carbon (C) is +4.
- Oxygen (O) is -2.
- For \( Na_2O_2 \):
- Sodium (Na) is +1.
- Oxygen (O) is -1.
- For \( CO_2 \):
- Carbon (C) is +4.
- Oxygen (O) is -2.
- For \( H_2O \):
- Hydrogen (H) is +1.
- Oxygen (O) is -2.

3. **Compare Oxidation States**:
- In \( H_2O_2 \), the oxidation state of oxygen is -1.
- In \( Na_2O_2 \), the oxidation state of oxygen is -1 (no change).
- In \( Na_2CO_3 \), carbon is +4 and remains +4 in \( CO_2 \) (no change).
- The oxidation state of carbon in \( Na_2CO_3 \) does not change, and the oxidation state of sodium remains +1 throughout.

4. **Identify Changes in Oxidation States**:
- The oxidation state of oxygen in \( H_2O_2 \) does not change to a higher oxidation state in \( Na_2O_2 \).
- The carbon in \( Na_2CO_3 \) remains +4 in \( CO_2 \).
- Therefore, there is no species that is losing electrons, which is a requirement for oxidation.

5. **Conclusion**:
- Since none of the substances undergo a change in oxidation state that indicates oxidation, we conclude that there is no substance undergoing oxidation in this reaction.

### Final Answer:
None of the substances in the reaction are undergoing oxidation.