An element which belongs to third period and group 16 in the periodic table has electronic configuration

Options

A. `1s^2,2s^22p^6,3s^23p^3``
B. `1s^2,2s^22p^6,3s^23p^4`
C. `1s^2,2s^22p^6,3s^23p^5`
D. `1s^2,2s^22p^4`

Answer

To find the electronic configuration of an element that belongs to the third period and group 16 of the periodic table, we can follow these steps:

### Step 1: Identify the Element
- The element in the third period and group 16 is Sulfur (S).

### Step 2: Determine the Period
- The third period indicates that the element has three principal energy levels (n=1, n=2, and n=3).

### Step 3: Determine the Group
- Group 16 elements are known as the chalcogens. They typically have six valence electrons.

### Step 4: Count the Total Electrons
- Sulfur has an atomic number of 16, which means it has 16 electrons.

### Step 5: Write the Electronic Configuration
- The electronic configuration is built by filling the orbitals according to the Aufbau principle:
1. The first shell (n=1) can hold 2 electrons: 1s²
2. The second shell (n=2) can hold 8 electrons: 2s² 2p⁶
3. The third shell (n=3) can hold the remaining electrons. Since sulfur has 16 electrons in total, after filling the first two shells, we have 16 - 10 = 6 electrons left for the third shell. Therefore, we fill the third shell as follows: 3s² 3p⁴.

- Combining these, the complete electronic configuration for sulfur is:
- **1s² 2s² 2p⁶ 3s² 3p⁴**

### Final Answer
The electronic configuration of the element that belongs to the third period and group 16 is **1s² 2s² 2p⁶ 3s² 3p⁴**.

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