When methyl halide reacts with sodium in the presence of dry ether it gives

Options

A. meethane
B. ethane
C. propane
D. butane

Answer

To solve the question, "When methyl halide reacts with sodium in the presence of dry ether, it gives," we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant is methyl halide, which can be represented as CH3-X, where X is a halogen (Cl, Br, I).

2. **Add Sodium**: When methyl halide reacts with sodium (Na), we need to consider that sodium will participate in the reaction. The reaction typically involves two moles of sodium.

3. **Presence of Dry Ether**: The reaction is carried out in the presence of dry ether, which acts as a solvent and helps stabilize the reaction intermediates.

4. **Formation of the Product**: The reaction between methyl halide and sodium leads to the formation of an alkane. Specifically, two methyl groups combine to form ethane (C2H6). The sodium halide (NaX) is also formed as a byproduct.

5. **Write the Balanced Reaction**:
\[ 2 \text{CH}_3\text{X} + 2 \text{Na} \rightarrow \text{C}_2\text{H}_6 + 2 \text{NaX} \]
Here, ethane (C2H6) is the main product formed along with sodium halide.

6. **Conclusion**: Thus, when methyl halide reacts with sodium in the presence of dry ether, the product formed is ethane (C2H6).

### Final Answer:
The product is ethane (C2H6).

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