When 2-methyl propane is oxidised in the presence of` KMnO_4`, then product formed is

Options

A. 2-methyl propanol
B. 1-methyl propan -2- ol
C. 2-methyl-propan -2- ol
D. 2,2 dimethyl ethanol

Answer

To determine the product formed when 2-methylpropane is oxidized in the presence of KMnO4, we will follow these steps:

### Step 1: Identify the structure of 2-methylpropane
2-methylpropane, also known as neopentane, has the following structure:

```
CH3
|
CH3 - C - CH3
|
CH3
```

It consists of a propane backbone with a methyl group attached to the second carbon.

### Step 2: Understand the oxidation process
KMnO4 (potassium permanganate) is a strong oxidizing agent. In organic chemistry, it is commonly used to oxidize alcohols, alkenes, and other functional groups. However, 2-methylpropane is an alkane, which is relatively stable and does not easily undergo oxidation.

### Step 3: Analyze the oxidation of alkanes
When alkanes are oxidized with KMnO4, they typically do not react significantly under mild conditions. Stronger conditions (like heat or concentrated KMnO4) may lead to cleavage of C-C bonds, but in the case of 2-methylpropane, it is unlikely to yield any significant products without extreme conditions.

### Step 4: Conclusion on the product
Since 2-methylpropane is a stable alkane and does not undergo oxidation under normal conditions with KMnO4, the product formed is essentially unchanged. Therefore, the product of the oxidation of 2-methylpropane in the presence of KMnO4 is:

**Product: 2-methylpropane (unchanged)**