I. 3-chloromethyl-2-isopropyl pentan-1-0l
II. 2,5-dimethylhexane-1,3-diol
III. 3-bromocyclohexanol
IV. Hex-1-en-3-ol
V. 2-bromo-3- methylpent-2-en-1-ol
Which of the following IUPAC names are considered as the isomeric alcohols of the molecular formula `C_6H_11OBr`?

Options

A. I ,II and III
B. II , III and IV
C. I, IV and V
D. III and V

Answer

To determine which of the given compounds are isomeric alcohols of the molecular formula C6H11OBr, we need to follow these steps:

### Step 1: Analyze the Molecular Formula
The molecular formula C6H11OBr indicates that the compound contains:
- 6 carbon atoms (C)
- 11 hydrogen atoms (H)
- 1 oxygen atom (O)
- 1 bromine atom (Br)

### Step 2: Identify the Given Compounds
We have the following compounds to analyze:
1. 3-chloromethyl-2-isopropyl pentan-1-ol
2. 2,5-dimethylhexane-1,3-diol
3. 3-bromocyclohexanol
4. Hex-1-en-3-ol
5. 2-bromo-3-methylpent-2-en-1-ol

### Step 3: Determine the Molecular Formula for Each Compound
We will calculate the molecular formula for each compound to see if it matches C6H11OBr.

1. **3-chloromethyl-2-isopropyl pentan-1-ol**
- This compound has 6 carbons, 13 hydrogens, 1 oxygen, and 1 chlorine.
- Formula: C6H13ClO (not isomeric)

2. **2,5-dimethylhexane-1,3-diol**
- This compound has 6 carbons, 14 hydrogens, and 2 oxygens.
- Formula: C6H14O2 (not isomeric)

3. **3-bromocyclohexanol**
- This compound has 6 carbons, 11 hydrogens, 1 oxygen, and 1 bromine.
- Formula: C6H11BrO (isomeric)

4. **Hex-1-en-3-ol**
- This compound has 6 carbons, 12 hydrogens, and 1 oxygen.
- Formula: C6H12O (not isomeric)

5. **2-bromo-3-methylpent-2-en-1-ol**
- This compound has 6 carbons, 11 hydrogens, 1 oxygen, and 1 bromine.
- Formula: C6H11BrO (isomeric)

### Step 4: Identify Isomeric Alcohols
From the analysis, the compounds that match the molecular formula C6H11OBr are:
- 3-bromocyclohexanol
- 2-bromo-3-methylpent-2-en-1-ol

### Conclusion
The isomeric alcohols of the molecular formula C6H11OBr are:
- **3-bromocyclohexanol**
- **2-bromo-3-methylpent-2-en-1-ol**