In presence of Cu catalyst,`(CH_3)_3COH` changes to

Options

A. `(CH_3)_2CO`
B. `(CH_3)_2C=CH_2`
C. `(CH_3)_2CO`
D. `CH_3CH_2CH=CH_2`

Answer

To solve the question, "In presence of Cu catalyst, (CH₃)₃COH changes to", we will follow these steps:

### Step 1: Identify the Compound
The given compound is (CH₃)₃COH, which is known as tert-butanol (or 2-methylpropan-2-ol). It is a tertiary alcohol because the carbon atom bonded to the hydroxyl (OH) group is connected to three other carbon atoms.

### Step 2: Understand the Reaction Conditions
The question states that the reaction occurs in the presence of a copper (Cu) catalyst at a temperature of approximately 573 K (300 °C). Under these conditions, tertiary alcohols undergo dehydration.

### Step 3: Dehydration Process
Dehydration is the process of removing a water molecule (H₂O) from the alcohol. For tert-butanol, the dehydration will involve the removal of the hydroxyl group (OH) and a hydrogen atom (H) from the adjacent carbon.

### Step 4: Formation of the Product
When tert-butanol undergoes dehydration, it forms a double bond between the two carbon atoms, resulting in the formation of an alkene. The product formed from the dehydration of tert-butanol is isobutylene (or isobutene), which has the structure:

```
CH3
|
CH2=C
|
CH3
```

### Step 5: Conclusion
Thus, the final product formed when (CH₃)₃COH is treated with a copper catalyst at high temperature is isobutylene.

### Final Answer:
In presence of Cu catalyst, (CH₃)₃COH changes to isobutylene (or isobutene).

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