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For the following acids (CH3)3CCH2CO2H...

For the following acids
`(CH_3)_3CCH_2CO_2H`
`(CH_3)_3N^+CH_2CO_2H`
`CH_3COOH`
`pK_a` value will be in order

A

`I gt II gt III`

B

`I lt II lt III`

C

`I gt III gt II`

D

`II gt III gt I`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of pKa values for the given acids, we need to analyze the structure and acidity of each compound. The lower the pKa value, the stronger the acid. Let's break down the given acids step by step. ### Step 1: Identify the Acids The acids given are: 1. **(CH₃)₃CCH₂CO₂H** (tert-butylacetic acid) 2. **(CH₃)₃N⁺CH₂CO₂H** (N,N-dimethylaminoacetic acid) 3. **CH₃COOH** (acetic acid) ### Step 2: Analyze Acidity - **Acetic Acid (CH₃COOH)**: This is a simple carboxylic acid. It has a pKa around 4.76. It is a weak acid but is more acidic than the others due to the lack of electron-donating groups that would destabilize the carboxylate ion formed upon deprotonation. - **N,N-dimethylaminoacetic Acid ((CH₃)₃N⁺CH₂CO₂H)**: This compound has a positively charged nitrogen. The presence of the positive charge can stabilize the conjugate base formed after deprotonation, making it more acidic than acetic acid. The pKa is expected to be lower than that of acetic acid. - **tert-butylacetic Acid ((CH₃)₃CCH₂CO₂H)**: This acid has three bulky alkyl groups (tert-butyl groups) attached to the carbon adjacent to the carboxylic acid. Alkyl groups are electron-donating, which destabilizes the negative charge on the conjugate base after deprotonation. Therefore, this acid is expected to be the least acidic among the three. ### Step 3: Order of Acidity Based on the analysis: - **Most acidic**: N,N-dimethylaminoacetic acid (pKa < 4.76) - **Moderately acidic**: Acetic acid (pKa ≈ 4.76) - **Least acidic**: tert-butylacetic acid (pKa > 4.76) ### Conclusion The order of pKa values from lowest to highest is: 1. **(CH₃)₃N⁺CH₂CO₂H** (lowest pKa) 2. **CH₃COOH** (middle pKa) 3. **(CH₃)₃CCH₂CO₂H** (highest pKa) ### Final Answer The order of pKa values will be: **(CH₃)₃N⁺CH₂CO₂H < CH₃COOH < (CH₃)₃CCH₂CO₂H** ---
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