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Two identical metal spheres are released...

Two identical metal spheres are released from the top of a tower after t seconds of each other such that they fall along the same vertical line. If air resistance is neglected, then at any instant of time during their fall,

A

the difference in their disptacament temain the same

B

the difference between thelr spaeds remains the same

C

the difference between their heights above ground Is proportional to `t^2`

D

the difference between their displacement Is proportional to t

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of two identical metal spheres released from the top of a tower, we will analyze their motion step by step. ### Step 1: Understanding the Problem We have two identical metal spheres released from a height \( H \) at different times. The first sphere is released at \( t = 0 \) seconds, and the second sphere is released after \( t \) seconds. We need to analyze their motion under the influence of gravity, neglecting air resistance. ### Step 2: Displacement of the First Sphere For the first sphere, which is released at \( t = 0 \): - Initial velocity \( u_1 = 0 \) - Time of fall \( t' \) (where \( t' \) is the time since it was released) Using the equation of motion: \[ s_1 = u_1 t' + \frac{1}{2} g t'^2 \] Since \( u_1 = 0 \): \[ s_1 = \frac{1}{2} g t'^2 \] ### Step 3: Displacement of the Second Sphere For the second sphere, which is released after \( t \) seconds: - Initial velocity \( u_2 = 0 \) - Time of fall \( t' - t \) (where \( t' \) is the time since the first sphere was released) Using the same equation of motion: \[ s_2 = u_2 (t' - t) + \frac{1}{2} g (t' - t)^2 \] Since \( u_2 = 0 \): \[ s_2 = \frac{1}{2} g (t' - t)^2 \] ### Step 4: Difference in Displacement Now, we calculate the difference in displacement between the two spheres: \[ \Delta s = s_1 - s_2 = \frac{1}{2} g t'^2 - \frac{1}{2} g (t' - t)^2 \] Expanding \( (t' - t)^2 \): \[ \Delta s = \frac{1}{2} g t'^2 - \frac{1}{2} g (t'^2 - 2tt' + t^2) \] \[ \Delta s = \frac{1}{2} g (2tt' - t^2) \] ### Step 5: Analyzing the Options 1. **Difference in displacement remains the same**: This is not true as we derived \( \Delta s = \frac{1}{2} g (2tt' - t^2) \), which depends on \( t' \). 2. **Difference in speeds remains the same**: The speed of the first sphere is \( v_1 = gt' \) and for the second sphere \( v_2 = g(t' - t) \). The difference \( |v_1 - v_2| = gt \), which is constant. 3. **Difference between heights above the ground is proportional to \( t^2 \)**: This is not true as we derived the difference in heights is not proportional to \( t^2 \). 4. **Difference between displacements is proportional to \( t \)**: This is also not true as it is dependent on \( t' \). ### Conclusion The correct answer is that the difference in speeds remains the same, which corresponds to option 2.
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