A Body moves a distance of 10 m along a straight line under the action of a force of 5N.if the work done is 25 joules the angle which the force makes with the direction of motion of the body is

Options

A. `0^0`
B. `30^0`
C. `60^0`
D. `90^0`

Answer

To solve the problem, we will use the formula for work done by a force:

### Step-by-Step Solution:

1. **Understand the Formula for Work Done**:
The work done \( W \) by a force \( F \) acting on an object that moves a distance \( D \) at an angle \( \theta \) to the direction of the force is given by:
\[ W = F \cdot D \cdot \cos(\theta) \]

2. **Identify Given Values**:
- Work done \( W = 25 \, \text{J} \)
- Force \( F = 5 \, \text{N} \)
- Distance \( D = 10 \, \text{m} \)

3. **Substitute the Values into the Formula**:
Plugging the known values into the work done formula:
\[ 25 = 5 \cdot 10 \cdot \cos(\theta) \]

4. **Simplify the Equation**:
Calculate \( 5 \cdot 10 \):
\[ 25 = 50 \cdot \cos(\theta) \]

5. **Isolate \( \cos(\theta) \)**:
Divide both sides by 50:
\[ \cos(\theta) = \frac{25}{50} = \frac{1}{2} \]

6. **Find the Angle \( \theta \)**:
We know that \( \cos(60^\circ) = \frac{1}{2} \). Therefore:
\[ \theta = 60^\circ \]

### Final Answer:
The angle which the force makes with the direction of motion of the body is \( 60^\circ \).

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