A force `F=-k/x_2(x!=0)` acts on a particle in x-direction. Find the work done by this force in displacing the particle from. `x = + a` to `x = 2a`. Here, k is a positive constant.

Options

A. `(3k)/(2a)`
B. `(4k)/a^2`
C. `-(3k)/(2a^2)`
D. `-(9k)/a^2`

Answer

A