If an object made of iron is immersed in water it displaces 8 kg of water how much is the buoyant force acting on the object in newton?(given g=`10ms^-2`)

Options

A. 50
B. 60
C. 70
D. 80

Answer

To find the buoyant force acting on an object immersed in water, we can use Archimedes' principle. According to this principle, the buoyant force is equal to the weight of the fluid displaced by the object.

### Step-by-Step Solution:

1. **Identify the mass of the water displaced**:
The problem states that the object displaces 8 kg of water.

2. **Calculate the weight of the displaced water**:
The weight of the displaced water can be calculated using the formula:
\[ \text{Weight} = \text{mass} \times g \]
where \( g \) is the acceleration due to gravity. Given \( g = 10 \, \text{m/s}^2 \), we can substitute the values:
\[ \text{Weight} = 8 \, \text{kg} \times 10 \, \text{m/s}^2 \]

3. **Perform the multiplication**:
\[ \text{Weight} = 80 \, \text{N} \]

4. **Conclusion**:
The buoyant force acting on the object is 80 N.

### Final Answer:
The buoyant force acting on the object is **80 Newtons**.

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