A solid of mass 600g has volume `450cm^3` then the relative density of the solid is

Options

A. 1.45
B. 1.32
C. 0.9
D. 0.5

Answer

To find the relative density of the solid, we can follow these steps:

### Step 1: Understand the concept of relative density
Relative density (also known as specific gravity) is defined as the ratio of the density of a substance to the density of a reference substance, typically water.

### Step 2: Calculate the density of the solid
Density is calculated using the formula:
\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
Given:
- Mass of the solid = 600 g
- Volume of the solid = 450 cm³

Substituting the values into the formula:
\[ \text{Density of the solid} = \frac{600 \, \text{g}}{450 \, \text{cm}^3} = \frac{600}{450} \, \text{g/cm}^3 \]

### Step 3: Simplify the density calculation
To simplify \(\frac{600}{450}\):
\[ \frac{600}{450} = \frac{600 \div 150}{450 \div 150} = \frac{4}{3} \, \text{g/cm}^3 \]

### Step 4: Calculate the relative density
The density of water is approximately \(1 \, \text{g/cm}^3\). Therefore, the relative density of the solid can be calculated as:
\[ \text{Relative Density} = \frac{\text{Density of the solid}}{\text{Density of water}} = \frac{\frac{4}{3} \, \text{g/cm}^3}{1 \, \text{g/cm}^3} = \frac{4}{3} \]

### Final Answer
The relative density of the solid is \(\frac{4}{3}\) or approximately \(1.33\).

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