In a closed circuit, the current / (in ampere) at an instant of time t (in second) is given by l = `4-0.08t`. The number of electrons flowing in 50 s through the cross-section of the conductor is

Options

A. `125xx10^(19)`
B. `625xx10^(20)`
C. `525xx10^(19)`
D. `2.55xx10^(20)`

Answer

B