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An object is placed 25 cm in front of a ...

An object is placed 25 cm in front of a concave lens of focal length 25 cm. The position of images is

A

- 10 cm

B

+ 10 cm

C

- 12 . 5 cm

D

12 . 5 cm

Text Solution

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The correct Answer is:
To find the position of the image formed by a concave lens when an object is placed in front of it, we can use the lens formula: ### Step 1: Write down the lens formula The lens formula is given by: \[ \frac{1}{V} - \frac{1}{U} = \frac{1}{F} \] where: - \( V \) = image distance from the lens - \( U \) = object distance from the lens - \( F \) = focal length of the lens ### Step 2: Identify the values In this case: - The focal length \( F \) of the concave lens is -25 cm (negative because it is a concave lens). - The object distance \( U \) is -25 cm (negative because the object is placed in front of the lens). ### Step 3: Substitute the values into the lens formula Substituting the values into the lens formula: \[ \frac{1}{V} - \frac{1}{-25} = \frac{1}{-25} \] ### Step 4: Simplify the equation Rearranging the equation gives: \[ \frac{1}{V} + \frac{1}{25} = -\frac{1}{25} \] \[ \frac{1}{V} = -\frac{1}{25} - \frac{1}{25} \] \[ \frac{1}{V} = -\frac{2}{25} \] ### Step 5: Calculate the image distance \( V \) Taking the reciprocal of both sides: \[ V = -\frac{25}{2} \text{ cm} \] This simplifies to: \[ V = -12.5 \text{ cm} \] ### Step 6: Conclusion The position of the image is at -12.5 cm from the lens, indicating that the image is formed on the same side as the object, which is typical for a concave lens.
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