The product obtained via oxymercuration`(HgSO_4+H_2SO_4)` Of but-1-yne would be

Options

A.
B. `CH_3-CH-2-CH-2-CHO`
C. `CH_3-CH_2-CHO+HCHO`
D. `CH_3-CH_2-COOH+HCOOH`

Answer

To determine the product obtained via oxymercuration of but-1-yne (CH₃CH₂C≡CH) using HgSO₄ and H₂SO₄, we can follow these steps:

### Step 1: Identify the reactants
The reactants are but-1-yne (an alkyne) and the reagents are mercuric sulfate (HgSO₄) and sulfuric acid (H₂SO₄).

### Step 2: Oxymercuration mechanism
In the oxymercuration reaction, the alkyne reacts with mercuric ion (Hg²⁺) from HgSO₄. The triple bond of but-1-yne will react with Hg²⁺ to form a mercurinium ion intermediate.

**Intermediate Formation:**
- The triple bond (C≡C) attacks the Hg²⁺ ion, forming a cyclic mercurinium ion where one carbon is bonded to the mercury atom.

### Step 3: Nucleophilic attack by water
In the presence of water (from H₂SO₄), the water molecule will act as a nucleophile and attack the more substituted carbon of the mercurinium ion. This is due to Markovnikov's rule, which states that the more substituted carbon will preferentially bond with the nucleophile.

**Intermediate Structure:**
- The structure will now have a hydroxyl group (OH) attached to the more substituted carbon and a mercury atom attached to the other carbon.

### Step 4: Deprotonation and product formation
After the nucleophilic attack, the next step involves deprotonation. The hydroxyl group (OH) will be protonated by H⁺ from the medium, leading to the formation of a carbonyl compound.

**Final Product:**
- The product formed is butan-2-one (CH₃C(=O)CH₂CH₃), which is a ketone. The mercury ion (Hg) will leave as a leaving group.

### Conclusion
The final product obtained from the oxymercuration of but-1-yne is butan-2-one (CH₃C(=O)CH₂CH₃).

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