Type of isomerism shown by the product of the reaction between benzaldehyde and hydroxylamine is

Options

A. syn and anti geometrical
B. cis and trans geometrical
C. E and Z geometrical
D. None is correct

Answer

To determine the type of isomerism shown by the product of the reaction between benzaldehyde and hydroxylamine, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this case are benzaldehyde (C6H5CHO) and hydroxylamine (NH2OH).

### Step 2: Write the Reaction
When benzaldehyde reacts with hydroxylamine, it forms an oxime. The reaction can be represented as follows:
\[ \text{C}_6\text{H}_5\text{CHO} + \text{NH}_2\text{OH} \rightarrow \text{C}_6\text{H}_5\text{C}(=N\text{OH})\text{H} + \text{H}_2\text{O} \]
The product formed is benzaldoxime.

### Step 3: Analyze the Product Structure
The structure of benzaldoxime can be represented as:
\[ \text{C}_6\text{H}_5\text{C}(=N\text{OH})\text{H} \]
In this structure, the nitrogen atom is bonded to the hydroxyl group (OH) and has a double bond with carbon.

### Step 4: Determine the Type of Isomerism
The product has a double bond between carbon and nitrogen (C=N). This allows for geometric isomerism (cis-trans isomerism) because of the different groups attached to the nitrogen atom.

1. **Cis Isomer**: When the hydroxyl group (OH) and the hydrogen atom (H) are on the same side of the double bond.
2. **Trans Isomer**: When the hydroxyl group (OH) and the hydrogen atom (H) are on opposite sides of the double bond.

### Step 5: Conclusion
Since the product can exist in two different geometric forms (cis and trans), the type of isomerism shown by the product of the reaction between benzaldehyde and hydroxylamine is **geometric isomerism** (specifically, cis-trans isomerism).

### Final Answer
The type of isomerism shown by the product of the reaction between benzaldehyde and hydroxylamine is **geometric isomerism** (cis-trans isomerism).

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