Find-
`tan^-1[(cosx-sinx)/(cosx+sinx)]`

tan^(-1)((cosx+sinx)/(cos x-sinx))

tan^-1(cosx/(1-sinx))

cot^(-1)((cosx-sinx)/(cosx+sinx))

Differentiate each of the following w.r.t. x: (i) tan^(-1)((1-cosx)/(sinx))" "(ii)tan^(-1)((cos x -sinx)/(cosx +sinx))

(x+sinx)/(1-cosx)

cosx-sinx=-1

cosx+sinx=1

Find the derivative of tan^(-1)((cosx - sinx)/(cosx + sinx)) with respect to 'x'

Show that tan^(-1)[(cosx+sinx)/(cosx-sinx)]=(pi)/(4)+x .