Home
Class 12
CHEMISTRY
Secondary amine with hinsberg reagent fo...

Secondary amine with hinsberg reagent forms (A) N-alkyl sulphonamide soluble in KOH solution. (B) N-alkyl sulphonamide insoluble in KOH solution (C) N-N-dialkyl sulphonamide soluble in KOH solution (D) N,N-dialkyl sulphonamide insoluble in KOH

Promotional Banner

Similar Questions

Explore conceptually related problems

Assertion (A): N-ethylbenzene sulphonamide is solube in alkali. Reason (R ): Hydrogen attached to nitrogen In sulphonamide is strongly acidic.

Assertion : N-Ethylbenzenessulphonamide is soluble in alkali . Reason : Hydrogen attached to nitrogen in sulphonamide is strongly acidic in nature .

What is the pH value of N/10^(7) KOH solution?

C_3H_6N racts with Hinsberg reagent and the product formed is insoluble in alkali but soluble in ether . What is C_3 H_9 N?

Ethanamine reacts with benzenesulfonyl chloride to form N-ethylbenzenesulfonamide which is underline("insoluble in KOH") .

Assertion(A): N,N-diethylbenzene sulphonamide is insoluble in alkali. Reason(R ): Sulphonyl group attached to nitrogen atoms is strong electron withdrawing group.

100 ml of 1M NaOH is mixed with 50ml of 1N KOH solution. Normality of mixture is

"40 ml "(N)/(10)HCl solution is mixed with 60 ml of (N)/(20)KOH solution. The resulting mixture will be

n-propyl bromide reacts with aqueous KOH to form:-

Calculate the volume of 0.2N solution required to prepare 200 mL of 0.05 N solution .