`int (3x^2+6) dx`

(3) int(x^(2)+5x+6)dx

(i) int (3x^2)/(x^6+1) dx (ii) int (3x)/(1+2x^4) dx

Evaluate I=int 1/(3x^2+4x+6)dx

(i) int (x dx)/(x^2+3x+2) (ii) int x/(x^2+5x+6) dx

Integrate: int 6x(3x^2+7)^7 dx

Integrate the following functions with respect to x (a) int (5x^2 + 3x -2) dx (b) int (4sin x-(2)/(x)) dx (c) int (dx)/(4x+5) (d) int (6x +2)^(3) dx

int cos(3x+6/1) dx

IF int_(-3)^2 f(x) dx=7/3 and int_(-3)^9 f(x) dx=-5/6 then what is the value of int_(2)^(9)f(x) dx

int ( x +2)/( 2x ^(2) + 6x + 5) dx = p int ( 4x +6)/( 2x ^(2) + 6x +5) dx + (1)/(2) int (1)/( 2x ^(2) + 6x + 5) dx then p

int6x e^(x^(2))dx=