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A positive magnification greater than un...

A positive magnification greater than unity indicates:

A

real image

B

virtual image

C

neither real not virtual image

D

distorted image

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The correct Answer is:
To determine what a positive magnification greater than unity indicates, we can analyze the concept of magnification in optics. ### Step-by-Step Solution: 1. **Understanding Magnification**: Magnification (m) is defined as the ratio of the height of the image (h') to the height of the object (h). It can also be expressed in terms of the distances of the image (v) and object (u) from the lens or mirror: \[ m = \frac{h'}{h} = \frac{v}{u} \] Here, \(h'\) is the height of the image, \(h\) is the height of the object, \(v\) is the distance of the image from the lens/mirror, and \(u\) is the distance of the object from the lens/mirror. 2. **Analyzing Positive Magnification**: A positive magnification indicates that the image is upright relative to the object. This means that the height of the image is in the same direction as the height of the object. 3. **Greater than Unity**: When magnification is greater than unity (m > 1), it implies that the height of the image is greater than the height of the object. This means that the image is larger than the object. 4. **Types of Images**: - A real image is formed when light rays converge and can be projected on a screen. Real images are typically inverted. - A virtual image is formed when light rays appear to diverge from a point. Virtual images cannot be projected on a screen and are typically upright. 5. **Conclusion**: Since we have a positive magnification greater than unity, it indicates that the image is not only upright but also larger than the object. This scenario typically occurs with virtual images formed by concave mirrors or converging lenses when the object is placed within the focal length. ### Final Answer: A positive magnification greater than unity indicates a **virtual image**. ---

To determine what a positive magnification greater than unity indicates, we can analyze the concept of magnification in optics. ### Step-by-Step Solution: 1. **Understanding Magnification**: Magnification (m) is defined as the ratio of the height of the image (h') to the height of the object (h). It can also be expressed in terms of the distances of the image (v) and object (u) from the lens or mirror: \[ m = \frac{h'}{h} = \frac{v}{u} ...
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  1. Name the part of a lens through which a ray of light passes without su...

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  2. In a simple microscope lens used is:

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  3. A positive magnification greater than unity indicates:

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  4. An object is placed 12 cm from a convex lens whose focal length is 10c...

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  5. The image produced by a concave lens is:

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  6. A virtual image is formed by:

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  7. Where should an object be placed in order of to use a convex lens as a...

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  8. Image formed by a convex mirror is

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  9. Image formed by plane mirror is :

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  10. The geometrical centre of surface of spherical mirror is called its

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  11. Define the principal focus of a concave mirror.

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  12. The splitting of light into its component colors is called :

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  13. Radius of curvature of a concave mirror is always ........ to the mirr...

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  14. The mirror used by dentists to concentrate light on the tooth to be ex...

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  15. An object is placed 1.5m from a plane mirror. How far is the image fro...

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  16. A drop of water appears like pear due to:

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  17. The radius of curvature of a plane mirror

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  18. Which one among the following is used to make periscope?

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  19. Which mirror has a wider field of view ?

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  20. Explain why, a ray of light passing through the centre of curvature of...

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