find-`dy/dx`
`ax^2+2hxy+by^2=0` where `h^2=ab`

If theta is the acute angle between the lines given by ax^(2) + 2hxy + by^(2) = 0 then prove that tan theta = |(2 sqrt (h^(2) - ab))/(a + b)| . Hence find acute angle between the lines 2x^(2) + 7xy + 3y^(2) = 0

If theta is the measure of acute angle between the pair of line repseented by ax^(2) + 2hxy + by^(2) = 0 , then prove that tan theta = |(2sqrt(h^(2) - ab))/(a+b)|,a + b ne 0 Hence find the acture angle between the lines x^(2) - 4xy + y^(2) = 0

ax^(2)+2hxy+by^(2)=0,then(dy)/(dx)=

If ax^(2)+2hxy+by^(2)=0 then (dy)/(dx)=

The ratio of the slopes of the lines represented by ax^(2)+2hxy+by^(2)=0 is 2:3 , then h^(2):ab=

If slopes of lines ax^(2)+2hxy+by^(2)=0 differ by k then (h^(2)-ab):b^(2)=

If the ratio of gradients of the line given by ax^(2)+2hxy+by^(2)=0 is 1:3 , then h^(2):ab=

The image of the pair of lines respresented by ax^2 + 2hxy + by^2 = 0 by the line mirror y = 0 is: (A) ax^2-2hxy+by^2=0 (b) bx^2-2hxy+ay^2=0 (c) bx^2+2hxy+ay^2=0 (d) ax^2-2hxy-by^2=0

Find dy/dx if : ax+by^(2)=cosy

Find (dy)/(dx) if ax+by^2=cosy