Home
Class 12
PHYSICS
A body of mass 5 kg starts from the orig...

A body of mass 5 kg starts from the origin with an initial velocity `bar(u)=(30hati+40hatj)ms^(-1)` .If a constant force `(-6hati-5hatj)N` acts on the body, the time in velocity, which the y-component of the velocity becomes zero is.

A

5 s

B

20 s

C

40 s

D

80 s

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

A body of mass 5 kg starts from the origin with an initial velocity vecu=30hati+40hatjms^(-1) . If a constant force vecF=-(hati+5hatj)N acts on the body, the time in which the y-component of the velocity becomes zero is

A body of mass 5 kg statrs from the origin with an initial velocity vec(u) = (30 hat(i) + 40 hat(j)) ms^(-1) . If a constant force (-6 hat(i) - 5 hat(j))N acts on the body, the time in which they component of the velocity becomes zero is

A particular has initial velocity , v=3hati+3hatj and a constant force F=4hati-3hatj acts on it. The path of the particle is

A body of mass 2kg is moving with a velocity of vecu=3hati+4hatj m//s .A steady force vecF=hati-2hatj N begins to act on it. After four second, the body will be moving along.

A body of mass 5 kg starts from the origin with an intial with an intial velocity vec (u) = 30hat(i) + 40hat(j). . If the body collides with a wall and after collision its velocity becomes vec(v) = - 30 hat (i) + 40 hat (j) , then what is change in momentum of body ?

A body of mass 0.8 kg has intial velocity (3hati-4hatj) ms^(-1) and final velocity (-6hatj+2hatk) ms^(-1) . Find change in kinetic energy of the body?