A block of wood of 1 kg resting on an inclined plane of angle `30^(@)`, just starts moving down. If the coefficient of friction is 0.2, then find its velocity (in `ms^(-1)`) after 5 s (take , `g=10ms^(-2)`)

A block of wood of 1kg resting on an inclined plane a angle 30^@ , just starts moving down. If the coefficient of friction is 0.2, then find its velocity (in ms^(-1) ) after 5s (take , g= 10ms^(-2) )

A body of 5 kg weight kept on a rough inclined plane of angle 30^(@) starts sliding with a constant velocity. Then the coefficient of friction is (assume g=10m//s^(2) )

If a block moving up an inclined plane at 30^(@) with a velocity of 5 m/s, stops after 0.5 s, then coefficient of friction will be nearly

A block slides down on inclined plane (angle of inclination 60^(@) ) with an accelration g//2 Find the coefficient friction

A block of mass 1 kg slides down on a rough inclined plane of inclination 60^(@) starting from its top. If the coefficient of kinetic friction is 0.5 and length of the plane is 1 m , then work done against friction is (Take g=9.8m//s^(2) )

If a block moving up an inclined plane at 30^(@) with a velocity of 5 m/s , stops after 0*5 s , then coefficient of friction will be nearly

A block weighing 10 kg just starts sliding down a rough inclined plane, which rises 5 in every 13 . What is the coefficient of friction ?

A block weighing 10 kg just starts sliding down a rough inclined plane, which rises 5 in every 13 . What is the coefficient of friction ?

When an automobile moving with a speed of 36km//h reaches an upward inclined road of angle 30^(@) , its engine is switched off. If the coefficient of friction is 0.1, how much distance will the automobile move before coming to rest ? Take g=10ms^(-2) .

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-