Home
Class 12
PHYSICS
A wooden box of mass 8kg slides down an ...

A wooden box of mass `8kg` slides down an inclined plane of inclination `30^(@)` to the horizontal with a constant acceleration of `0.4ms^(-2)` What is the force of friction between the box and inclined plane ? `(g = 10m//s^(2))` .

A

36.8N

B

65.6N

C

76.8N

D

63.8N

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A block of mass 10kg is pushed up on a smooth incline plane of inclination 30^(@) , so that it has acceleration 2m//s^(2) . The applied force is

A block of mass 8 kg is sliding on a surface inclined at an angle of 45^(@) with the horizontal. Calculate the acceleration of the block. The coefficient of friction between the block and surface is 0.6. (Take g=10m//s^(2) )

A block of mas m begins to slide down on an inclined plane of inclination theta . The force of friction will be

A body of mass 100 g is sliding from an inclined plane of inclination 30^(@) . What is the frictional force experienced if mu=1.7 .

A block slides down on inclined plane (angle of inclination 60^(@) ) with an accelration g//2 Find the coefficient friction

A body of mass 10kg is placed on a smooth inclined plane making an angle of 30^(@) with the horizontal, the component of the force of gravity trying to move the body down the inclined plane is [g=9.8m//s^(2)]

A block slides down a plane. Inclined at 30^(@) to the horizontal, with an acceleration a. A disc rolling without slipping down the same inclined plane would have an acceleration

A block of mass m slides down an inclined plane of inclination theta with uniform speed. The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is

A block of mass m slides down an inclined plane of inclination theta with uniform speed The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is .