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A force F=-k/x2(x!=0) acts on a particle...

A force `F=-k/x_2(x!=0)` acts on a particle in x-direction. Find the work done by this force in displacing the particle from. `x = + a` to `x = 2a`. Here, k is a positive constant.

A

`-h/(2a)`

B

`k//2a`

C

`2a//k`

D

`a//R`

Text Solution

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The correct Answer is:
A
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