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The angular position of a point on a rot...

The angular position of a point on a rotating wheel is given by `theta=2.0+4.0t^(2)+2.0t^(3)`, where `theta` is in radians and t is in seconds. At t = 0, what are (a) the point's angular position and (b) its angular velocity? ( c) What is its angular velocity at t = 3.0 s? (d) Calculate its angular acceleration at t = 4.0 s. (e) Is its angular acceleration constant?

A

`2rad,0rad//s,8rad//s^2`

B

`7.5rad//s^2,0rad,2rad//s`

C

`6rad//s^2,8rad,0rad//s`

D

`8.5rad//s^2,8rad,0rad//s`

Text Solution

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The correct Answer is:
A
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