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Two bodies of 6 kg and 4 kg masses have ...

Two bodies of 6 kg and 4 kg masses have their velocity `5hati-2hatj+10hatk` and `10hati-2hatj+5hatk`, respectively. Then, the velocity of their centre of mass is

A

`5hati+2hatj-8hatk`

B

`7hati+2hatj-8hatk`

C

`7hati-2hatj+8hatk`

D

`5hati-2hatj+8hatk`

Text Solution

AI Generated Solution

The correct Answer is:
To find the velocity of the center of mass (V_cm) of two bodies with given masses and velocities, we can follow these steps: ### Step 1: Identify the masses and velocities - Mass of body 1 (m1) = 6 kg - Velocity of body 1 (v1) = \(5 \hat{i} - 2 \hat{j} + 10 \hat{k}\) m/s - Mass of body 2 (m2) = 4 kg - Velocity of body 2 (v2) = \(10 \hat{i} - 2 \hat{j} + 5 \hat{k}\) m/s ### Step 2: Use the formula for the velocity of the center of mass The formula for the velocity of the center of mass is given by: \[ V_{cm} = \frac{m_1 v_1 + m_2 v_2}{m_1 + m_2} \] ### Step 3: Calculate the total momentum in each direction We will calculate the momentum in the x, y, and z directions separately. #### For the x-direction: \[ V_{cm_x} = \frac{m_1 v_{1x} + m_2 v_{2x}}{m_1 + m_2} \] Where: - \(v_{1x} = 5\) m/s - \(v_{2x} = 10\) m/s Calculating: \[ V_{cm_x} = \frac{6 \times 5 + 4 \times 10}{6 + 4} = \frac{30 + 40}{10} = \frac{70}{10} = 7 \text{ m/s} \] #### For the y-direction: \[ V_{cm_y} = \frac{m_1 v_{1y} + m_2 v_{2y}}{m_1 + m_2} \] Where: - \(v_{1y} = -2\) m/s - \(v_{2y} = -2\) m/s Calculating: \[ V_{cm_y} = \frac{6 \times (-2) + 4 \times (-2)}{6 + 4} = \frac{-12 - 8}{10} = \frac{-20}{10} = -2 \text{ m/s} \] #### For the z-direction: \[ V_{cm_z} = \frac{m_1 v_{1z} + m_2 v_{2z}}{m_1 + m_2} \] Where: - \(v_{1z} = 10\) m/s - \(v_{2z} = 5\) m/s Calculating: \[ V_{cm_z} = \frac{6 \times 10 + 4 \times 5}{6 + 4} = \frac{60 + 20}{10} = \frac{80}{10} = 8 \text{ m/s} \] ### Step 4: Combine the components to find V_cm Now we can combine the components to find the velocity of the center of mass: \[ V_{cm} = V_{cm_x} \hat{i} + V_{cm_y} \hat{j} + V_{cm_z} \hat{k} \] Substituting the values: \[ V_{cm} = 7 \hat{i} - 2 \hat{j} + 8 \hat{k} \text{ m/s} \] ### Final Answer: The velocity of the center of mass is: \[ \boxed{7 \hat{i} - 2 \hat{j} + 8 \hat{k} \text{ m/s}} \]
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