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The motion of a particle in S.H.M. is de...

The motion of a particle in S.H.M. is described by the displacement function, `x=Acos(omegat+phi)`, If the initial `(t=0)` position of the particle is 1cm and its initial velocity is `omega cm s^(-1)`, what are its amplitude and initial phase angle ? The angular frequency of the particle is `pis^(-1)`. If instead of the cosine function, we choose the sine function to describe the SHM`: x=B sin(omegat+alpha)`, what are the amplitude and initial phase of the particle with the above initial conditions ?

A

`sqrt2,pi/4`

B

`sqrt3,pi/5`

C

`pi/4,sqrt2`

D

`pi/5,sqrt3`

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The correct Answer is:
A
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