Home
Class 12
PHYSICS
A particle executing SHM of amplitude 4 ...

A particle executing SHM of amplitude 4 cm and T = 4s. The time taken by it to move from positive extreme position to half the amplitude is

A

1 s

B

`1/3s`

C

`2/3s`

D

`sqrt(3/2)s`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle excuting S.H.M. of amplitude 4 cm and T = 4 sec .The time take by it to move position extreme position to half the amplitude is

A particle executing SHM of amplitude 4 cm and T=4 s .The time taken by it to move from position to half the amplitude is

A particle is executing SHM of amplitude 4cm and time period 12s . The time taken by the particle in going from its mean position to a position of displacement equal to 2cm is T_1 . The time taken from this displaced position to reach the extreme position on the same side is T_2.T_1//T_2 is

A particle executes linear SHM with time period of 12 second. Minimum time taken by it to travel from positive extreme to half of the amplitude is

A particle executes S.H.M with time period 12 s. The time taken by the particle to go directly from its mean position to half its amplitude.

A particle executes SHM with a time period of 4 s . Find the time taken by the particle to go from its mean position to half of its amplitude . Assume motion of particle to start from mean position.

A particle executing a simple harmonic motion has a period of 6 s. The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is

A particle is executing SHM of periodic time T the time taken by a particle in moving from mean position to half the maximum displacement is (sin 30^(@)=0.5)