Home
Class 12
PHYSICS
The time period of a simple pendulum ins...

The time period of a simple pendulum inside a stationary lift is `sqrt(5)` s. What will be the time period when the lift moves upward with an acceleration `(g)/(4)`?

A

`sqrt5s`

B

`2sqrt5s`

C

`(2+sqrt5)s`

D

2 s

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The time period of a simple pendulum inside a starionary lift is 2 second. What would be its period, when the lift moves upwards with an acceleration (g)/(4) ?

Time period of a simple pendulum inside a satellite orbiting earth is

Time period of a simple pendulum in a freely falling lift will be

The time period of a simple pendulum is T remaining at rest inside a lift. Find the time period of pendulum when lift starts to move up with an acceleration of g/4

The time period of a simple pendulum oscillating in a freely falling lift is

The time period of a simple pendulum measured inside a stationary lift is found to be T . If the lift starts accelerating upwards with an acceleration g //3 , the time period is

A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. if the lift accelerates upwards with an acceleration g/4, then the period of the pendulum will be

A simple pendulum is hung in a stationary lift and its periodic time is T. What will be the effect on its periodic time T if the lift goes up with uniform acceleration a ?

The time period of a simple pendulum inside a stationary lift is T. If it starts descending with acceleration g/5. the new period of the simple pendulum will be