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The value of permittivity of free Space ...

The value of permittivity of free Space is

A

`9xx10^9Nm^2//C^2`

B

`8.85xx10^-12Nm^2//C^2-5`

C

`8.85xx10^-12C^2//Nm^2`

D

`9xx10^9C^2//Nm^2`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • The unit of permittivity of free space epsilon_(0) is:

    A
    `"coulomb"//"newton" - "metre"`
    B
    `"newton"-metre^(2)//"coulomb"^(2)`
    C
    `"coulomb"^(2)//"newton" - "metre"^(2)`
    D
    `"coulomb"^(2)//("newton" - "metre")^(2)`

  • The unitof permittivity of free space epsilon_(0) is

    A
    coulomb `//` newton-metre
    B
    coulom`b^(2) //`newton -metre`^(2)`
    C
    newton-metr`e^(2) //`coulom`b^(2)`
    D
    coulom`b^(2) //`(newton-metre`)^(2)`

  • If the electric flux entering and leaving a closed surface are 6 xx 10^6 and 9 xx 10^6 SI units respectively, then the net charge inside the surface of permittivity of free space epsilon_0 is

    A
    `epsilon_0xx10^6`
    B
    `-epsilon_0xx10^6`
    C
    `-2epsilon_0 xx10^6`
    D
    `3epsilon_0xx10^6`

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