Home
Class 12
PHYSICS
In L-C circuit, the charge oscillates wi...

In L-C circuit, the charge oscillates with a natural frequency `omega_0` given by

A

`omega_0 = 1/(LC)`

B

`omega_0 = 1/sqrt(LC)`

C

`omega_0 = 1/(2LC)`

D

`omega_0 = 1/sqrt(2LC)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the natural frequency \(\omega_0\) of an LC circuit, we can follow these steps: ### Step-by-Step Solution 1. **Understand the Components of the LC Circuit**: - An LC circuit consists of an inductor (L) and a capacitor (C) connected together. The inductor stores energy in its magnetic field, while the capacitor stores energy in its electric field. 2. **Identify Reactances**: - The capacitive reactance \(X_C\) is given by the formula: \[ X_C = \frac{1}{\omega_0 C} \] - The inductive reactance \(X_L\) is given by the formula: \[ X_L = \omega_0 L \] 3. **Set the Reactances Equal**: - At resonance in an LC circuit, the capacitive reactance equals the inductive reactance: \[ X_C = X_L \] - This leads to the equation: \[ \frac{1}{\omega_0 C} = \omega_0 L \] 4. **Rearrange the Equation**: - Multiply both sides by \(\omega_0 C\): \[ 1 = \omega_0^2 LC \] 5. **Solve for \(\omega_0\)**: - Rearranging the equation gives: \[ \omega_0^2 = \frac{1}{LC} \] - Taking the square root of both sides results in: \[ \omega_0 = \frac{1}{\sqrt{LC}} \] 6. **Conclusion**: - The natural frequency \(\omega_0\) of the LC circuit is given by: \[ \omega_0 = \frac{1}{\sqrt{LC}} \] ### Final Answer: The natural frequency \(\omega_0\) of the LC circuit is: \[ \omega_0 = \frac{1}{\sqrt{LC}} \]
Promotional Banner

Similar Questions

Explore conceptually related problems

An inductor of inductance 2 mH is connected across a charged capacitor of capacitance 5 mu F and the L-C circuit is set oscillating at its natural frequency. What is the natural angular frequency of its oscillations?

A non-resistive inductor is connected across a fully charged capacitor and the L-C circuit is set oscillating at its natural frequency. What is the value of the current when the charge on the capacitor has the maximum value of 100 mu C ?

In R-L-C series circuit, we have same current at angular frequencies omega_(1) and omega_(2) . The resonant frequency of circuit is

In an oscillator, frequency of oscillations is given by

In a series R-L-C circuit, the frequency of the source is half of the resonance frequency. The nature of the circuit will be